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research:memos:inverse_compton_scattering [2022/07/25 00:29] – [General formula] kobayashresearch:memos:inverse_compton_scattering [2022/07/28 23:29] (現在) – [General formula] kobayash
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 From the laws of conservation of the energy and the momentum, From the laws of conservation of the energy and the momentum,
 \begin{align} \begin{align}
-E_e + p_{\mathrm{ph}}c = E_e^\prime + p_{\mathrm{ph}}^{\prime}c\\+E_e + p_{\mathrm{ph}}c = E_e^\prime + p_{\mathrm{ph}}^{\prime}c,\\
 \boldsymbol{p}_e + \boldsymbol{p}_{\mathrm{ph}} = \boldsymbol{p}_e^\prime + \boldsymbol{p}_{\mathrm{ph}}^{\prime}.\\ \boldsymbol{p}_e + \boldsymbol{p}_{\mathrm{ph}} = \boldsymbol{p}_e^\prime + \boldsymbol{p}_{\mathrm{ph}}^{\prime}.\\
 \end{align} \end{align}
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 E_e^{\prime 2} = E_e^2 + p_{\mathrm{ph}}^2c^2 + p_{\mathrm{ph}}^{\prime 2}c^2 + 2E_e p_{\mathrm{ph}}c - 2E_e p_{\mathrm{ph}}^{\prime}c -2p_{\mathrm{ph}} p_{\mathrm{ph}}^{\prime}c^2.\\ E_e^{\prime 2} = E_e^2 + p_{\mathrm{ph}}^2c^2 + p_{\mathrm{ph}}^{\prime 2}c^2 + 2E_e p_{\mathrm{ph}}c - 2E_e p_{\mathrm{ph}}^{\prime}c -2p_{\mathrm{ph}} p_{\mathrm{ph}}^{\prime}c^2.\\
 \end{align} \end{align}
-By using $E^2 = m^2c^4 + p^2c^2$,+By using $E_e^2 = m_e^2c^4 + p_e^2c^2$ and $E_e^{\prime 2} = m_e^2c^4 + p_e^{\prime 2}c^2$
 \begin{align} \begin{align}
-m_e^2c^4  + p_e^{\prime 2}c^2 &= m_e^2c^4  + p_e^{\prime 2}c^2 + p_{\mathrm{ph}}^2c^2 + p_{\mathrm{ph}}^{\prime 2}c^2 + 2E_e p_{\mathrm{ph}}c - 2E_e p_{\mathrm{ph}}^{\prime}c -2p_{\mathrm{ph}} p_{\mathrm{ph}}^{\prime}c^2\\+m_e^2c^4  + p_e^{\prime 2}c^2 &= m_e^2c^4  + p_e^2c^2 + p_{\mathrm{ph}}^2c^2 + p_{\mathrm{ph}}^{\prime 2}c^2 + 2E_e p_{\mathrm{ph}}c - 2E_e p_{\mathrm{ph}}^{\prime}c -2p_{\mathrm{ph}} p_{\mathrm{ph}}^{\prime}c^2\\
 \Leftrightarrow \  \Leftrightarrow \ 
 p_e^{\prime 2}c^2 &= p_e^2c^2 + p_{\mathrm{ph}}^2c^2 + p_{\mathrm{ph}}^{\prime 2}c^2 + 2E_e p_{\mathrm{ph}}c - 2E_e p_{\mathrm{ph}}^{\prime}c -2p_{\mathrm{ph}} p_{\mathrm{ph}}^{\prime}c^2.\\ p_e^{\prime 2}c^2 &= p_e^2c^2 + p_{\mathrm{ph}}^2c^2 + p_{\mathrm{ph}}^{\prime 2}c^2 + 2E_e p_{\mathrm{ph}}c - 2E_e p_{\mathrm{ph}}^{\prime}c -2p_{\mathrm{ph}} p_{\mathrm{ph}}^{\prime}c^2.\\
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 \end{align} \end{align}
  
-If unit vectors $\widehat{\boldsymbol{p}_{\mathrm{ph}}^{\prime}} = \boldsymbol{p}_{\mathrm{ph}}^{\prime}/p_{\mathrm{ph}}^{\prime},\ \widehat{\boldsymbol{p}_{\mathrm{ph}}} = \boldsymbol{p}_{\mathrm{ph}}/p_{\mathrm{ph}}$, and $\widehat{\boldsymbol{p}_e} = \boldsymbol{p}_e/p_e$ is defined,+If unit vectors $\widehat{\boldsymbol{p}_{\mathrm{ph}}^{\prime}} = \boldsymbol{p}_{\mathrm{ph}}^{\prime}/p_{\mathrm{ph}}^{\prime},\ \widehat{\boldsymbol{p}_{\mathrm{ph}}} = \boldsymbol{p}_{\mathrm{ph}}/p_{\mathrm{ph}}$, and $\widehat{\boldsymbol{p}_e} = \boldsymbol{p}_e/p_e$ are defined,
 \begin{align} \begin{align}
 |\boldsymbol{p}_e + \boldsymbol{p}_{\mathrm{ph}}| \cos \theta_{\mathrm{ph}}^{\prime} |\boldsymbol{p}_e + \boldsymbol{p}_{\mathrm{ph}}| \cos \theta_{\mathrm{ph}}^{\prime}
research/memos/inverse_compton_scattering.1658676593.txt.gz · 最終更新: 2022/07/25 00:29 by kobayash
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